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(P)=10P^2+1760-50000
We move all terms to the left:
(P)-(10P^2+1760-50000)=0
We get rid of parentheses
-10P^2+P-1760+50000=0
We add all the numbers together, and all the variables
-10P^2+P+48240=0
a = -10; b = 1; c = +48240;
Δ = b2-4ac
Δ = 12-4·(-10)·48240
Δ = 1929601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1929601}}{2*-10}=\frac{-1-\sqrt{1929601}}{-20} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1929601}}{2*-10}=\frac{-1+\sqrt{1929601}}{-20} $
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